Richard Bucker

default value bug in python???

Posted at — Apr 7, 2012

One of the annoying things about languages, specially dynamic languages, is some of the odd side effects. This is particularly challenging when trying to debug moderately complex or involved code fragments. ┬áHere an interesting code sample that I’m looking at right now: 3 4 def func(a, b, c={}): 5 if c: 6 print ‘something is wrong’ 7 d = a+b 8 c[‘a’] = a 9 c[‘b’] = b 10 c[’d'] = d 11 return c 12 13 14 print func(1,2) 15 print func(1,2) 16In the function declaration I set c with a default value {} which is an empty dict. And unless I provide the 3rd param I would expect c to be empty every time. However when I execute this function I get something different:$ python{‘a’: 1, ‘b’: 2, ’d': 3}something is wrong{‘a’: 1, ‘b’: 2, ’d': 3}Notice that the message “something is wrong” is displayed. ┬áThat means that the second call to func() is ignoring the emptyhash or it’s actually something completely different. The possible choices are: (1) {} defines a semi-static-scoped reference and not a new heap instance. (2) the ‘=’ assignment in the function prototype does not actually work as you would expect.The lesson here might be more than is there a bug in the language design or implementation. More importantly it supports my A-1 best practice … stay in the sweet spot.